# Linear Model Power Analysis with Dplyr

I really liked the power analysis example I gave in class today. I feel like I’m finally firing on all cylinders with the tidyverse. So I thought I would post it here, in case it was of use to anyone!

### Power

OK, we can fit and evluate linear regression models, but what about their power? Let’s look at our seal fit again – maybe we want to know what would have happened with a lower sample size?

Note, I’m going to use a knitr function, kable to neaten up the table for markdown. Try it in your own homeworks!

knitr::kable(tidy(seal_lm))
term estimate std.error statistic p.value
(Intercept) 115.7667505 0.1763751 656.3668 0
age.days 0.0023706 0.0000447 53.0645 0

knitr::kable(glance(seal_lm)[,1:3])
0.2256493 0.2255691 5.6805

All right – there are our target values. Now, we can change a lof ot things. The effect size (slope), range of values, sigma, and more. But let’s try sample size.

###### 1 Make a Table of Parameters, some of which vary

The first step of a power analysis is to setup a data frame with all of the different possibilities that you might want to assess for power. For linear regression, we have the following parameters, all of which might vary:

1. Slope
2. Intercept
3. Residual variance
4. Sample Size
5. Range of X values

To do a power analysis via simulation for a linear regression, we begin by building our simulation data frame with the parameters and information that varies. In this case, sample size.

library(dplyr)

set.seed(607)

simPopN <- data.frame(slope = 0.00237,
intercept=115.767,
sigma = 5.6805,
n=10:100) 

Note, if we wanted to vary more than one parameter, we’d first create a data frame where only one parameter varied, then add a second that varried using crossing in tidyr, like so:

library(tidyr)

simPopN <- data.frame(slope = 0.00237,
intercept=115.767,
sigma = 2:6) %>%
crossing(n=10:100) 
###### 2 Expand to have a number of rows for each simulated sample with each parameter combination

OK, once we have everything in place, including sample size, we need to expand this out to have some number of samples for each n. For that, we can use the function in tidyr (same library as crossings), expand().

library(tidyr)

simPopN <- simPopN %>%
group_by(slope, intercept, sigma, n) %>%
expand(reps = 1:n) %>%
ungroup()
###### 3 Expand to create repeated simulated data sets for each combination of parameters

Now, if we want to simulate each of these, say, 100 times, we need to assign unique sim numbers, so for each n and sim number we have a unique data set. We can use crossing to replicate each combination of variables above some number of times. Note – 100 is really low, but it doesn’t eat your processor! Use low numbers of simulation for development, then crank them up for final analysis.

simPopN <- simPopN  %>%
crossing(sim = 1:100)
###### 3 Simulate the data

Great – almost ready to go! Now we just need to add in fitted values. Fortunately, as rnorm() works with vectors, we can just use a mutate here. We’ll also need to simulate random draws of ages, but that’s just another random number.

simPopN <- simPopN %>%
mutate(age.days = runif(n(), 1000, 8500)) %>%
mutate(length.cm = rnorm(n(), intercept + slope*age.days, sigma))

###### 4 Fit models and extract coefficients

First, we now need to generate a lot of fit models. Dplyr doesn’t take too kindly to including fit things, so, we can use two powerful functions here – first, nest and unnest() allow us to collapse grouped data down into little pieces and re-expand it.

fits <- simPopN %>%
group_by(slope, intercept, sigma, n, sim) %>%
nest()

fits
## # A tibble: 9,100 × 6
##      slope intercept  sigma     n   sim              data
##      <dbl>     <dbl>  <dbl> <int> <int>            <list>
## 1  0.00237   115.767 5.6805    10     1 <tibble [10 × 3]>
## 2  0.00237   115.767 5.6805    10     2 <tibble [10 × 3]>
## 3  0.00237   115.767 5.6805    10     3 <tibble [10 × 3]>
## 4  0.00237   115.767 5.6805    10     4 <tibble [10 × 3]>
## 5  0.00237   115.767 5.6805    10     5 <tibble [10 × 3]>
## 6  0.00237   115.767 5.6805    10     6 <tibble [10 × 3]>
## 7  0.00237   115.767 5.6805    10     7 <tibble [10 × 3]>
## 8  0.00237   115.767 5.6805    10     8 <tibble [10 × 3]>
## 9  0.00237   115.767 5.6805    10     9 <tibble [10 × 3]>
## 10 0.00237   115.767 5.6805    10    10 <tibble [10 × 3]>
## # ... with 9,090 more rows

Second, the map function in the purrr library allows us to iterate over different levels or grouped data frames, and perform some function. In this case, we’ll fit a model, get it’s coefficients using broom. This is a new weird set of functions. What’s odd about map is that the first argument is a column. But that argument, for the rest of the arguments of the function, is now called . and we also use the ~ notation. What ~ does is says that, from this point forward, . refers to the first argument given to map.

In essence, what map does is iterate over each element of a list given to it. Once we nest, the data column is now a list, with each element of the list it’s own unique data frame. So, map works with lists to apply a function to each element. The output of the model fitting is another list – now called mod. A list of models. We then iterate, using map over that list to generate another list of data frames – this time of coefficients.

library(purrr)
library(broom)

fits <- fits %>%
mutate(mod = map(data, ~lm(length.cm ~ age.days, data=.))) %>%
mutate(coefs = map(mod, ~tidy(.)))

fits  
## # A tibble: 9,100 × 8
##      slope intercept  sigma     n   sim              data      mod
##      <dbl>     <dbl>  <dbl> <int> <int>            <list>   <list>
## 1  0.00237   115.767 5.6805    10     1 <tibble [10 × 3]> <S3: lm>
## 2  0.00237   115.767 5.6805    10     2 <tibble [10 × 3]> <S3: lm>
## 3  0.00237   115.767 5.6805    10     3 <tibble [10 × 3]> <S3: lm>
## 4  0.00237   115.767 5.6805    10     4 <tibble [10 × 3]> <S3: lm>
## 5  0.00237   115.767 5.6805    10     5 <tibble [10 × 3]> <S3: lm>
## 6  0.00237   115.767 5.6805    10     6 <tibble [10 × 3]> <S3: lm>
## 7  0.00237   115.767 5.6805    10     7 <tibble [10 × 3]> <S3: lm>
## 8  0.00237   115.767 5.6805    10     8 <tibble [10 × 3]> <S3: lm>
## 9  0.00237   115.767 5.6805    10     9 <tibble [10 × 3]> <S3: lm>
## 10 0.00237   115.767 5.6805    10    10 <tibble [10 × 3]> <S3: lm>
## # ... with 9,090 more rows, and 1 more variables: coefs <list>

Last, we cleanup – we unnest, which takes list-columns from above, and expands them out as into full data frames that get slotted back into our original data frame. Nice trick, no?

We’ll also filter for just the slope coefficient.

fits <- fits %>%
unnest(coefs) %>%
ungroup() %>%
filter(term == "age.days")

fits
## # A tibble: 9,100 × 10
##      slope intercept  sigma     n   sim     term     estimate    std.error
##      <dbl>     <dbl>  <dbl> <int> <int>    <chr>        <dbl>        <dbl>
## 1  0.00237   115.767 5.6805    10     1 age.days 0.0004283944 0.0010318274
## 2  0.00237   115.767 5.6805    10     2 age.days 0.0021239104 0.0005736028
## 3  0.00237   115.767 5.6805    10     3 age.days 0.0033531879 0.0009399613
## 4  0.00237   115.767 5.6805    10     4 age.days 0.0032566962 0.0008342080
## 5  0.00237   115.767 5.6805    10     5 age.days 0.0028332982 0.0009062293
## 6  0.00237   115.767 5.6805    10     6 age.days 0.0028501936 0.0005176723
## 7  0.00237   115.767 5.6805    10     7 age.days 0.0021677718 0.0004457464
## 8  0.00237   115.767 5.6805    10     8 age.days 0.0034636535 0.0006116823
## 9  0.00237   115.767 5.6805    10     9 age.days 0.0012147324 0.0012945056
## 10 0.00237   115.767 5.6805    10    10 age.days 0.0039061730 0.0011307423
## # ... with 9,090 more rows, and 2 more variables: statistic <dbl>,
## #   p.value <dbl>

Notice that we do indeed have p-values, so we can use these fits to get power for each sample size. We can now do our normal process – in this case grouping by sample size – to get power. And then we can plot the result!

pow <- fits %>%
group_by(n) %>%
summarise(power = 1-sum(p.value>0.05)/n()) %>%
ungroup()

qplot(n, power,  data=pow, geom=c("point", "line")) +
theme_bw(base_size=17) +
geom_hline(yintercept=0.8, lty=2)

###### 6. Examples

Let’s take a look at the whole workflow, this time trying a bunch of standard deviation values.

##setup parameters
simSD <- data.frame(slope = 0.00237,
intercept=115.767,
sigma = seq(2:6, lengthout=5),
n=100) %>%
group_by(slope, intercept, sigma, n) %>%

expand(reps = 1:n) %>%

crossing(sim = 1:100) %>%

mutate(age.days = runif(n(), 1000, 8500)) %>%
mutate(length.cm = rnorm(n(), intercept + slope*age.days, sigma))

fitsSD <- simSD %>%
group_by(slope, intercept, sigma, n, sim) %>%
nest()%>%

#mapping
mutate(mod = map(data, ~lm(length.cm ~ age.days, data=.))) %>%
mutate(coefs = map(mod, ~tidy(.)))%>%

#unnest and filter
unnest(coefs) %>%
ungroup() %>%
filter(term == "age.days")

##calculate and plot power
powSD <- fitsSD %>% group_by(n) %>%
summarise(power = 1-sum(p.value>0.05)/n()) %>%
ungroup()

qplot(n, power,  data=powSD, geom=c("point", "line")) +
theme_bw(base_size=17) +
geom_hline(yintercept=0.8, lty=2)